Y=5x^2+2x+1

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Solution for Y=5x^2+2x+1 equation: 



=5Y^2+2Y+1

We move all terms to the left:

-(5Y^2+2Y+1)=0

We get rid of parentheses

-5Y^2-2Y-1=0

a = -5; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-5)·(-1)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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